Ask Question
23 November, 23:03

A ball is launched into the sky at 272 feet per second from the roof of a skyscraper 1,344 feet tall. The equation for the ball's height h at time t seconds is h = - 16t2 + 272t + 1344. When will the ball strike the ground?

+1
Answers (1)
  1. 24 November, 03:01
    0
    The answer is - 16 (t+4) (t-21)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A ball is launched into the sky at 272 feet per second from the roof of a skyscraper 1,344 feet tall. The equation for the ball's height h ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers