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15 April, 09:55

The length of a rectangle is 4 less than twice the width. The area of the rectangle is 70 square feet. Find the width, w, of the rectangle algebraically. Explain why one of the solutions for w is not viable.

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  1. 15 April, 12:19
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    Area = Length * Width

    Length = 2w - 4

    Width = w

    70 = (2w - 4) w

    70 = 2w² - 4w

    2w² - 4w - 70 = 0

    2 (w² - 2w - 35) = 0

    2 (w + 5) (w - 7) = 0

    w + 5 = 0; w - 7 = 0

    w = - 5; w = 7

    w = - 5 is not viable because no length of measurement is negative.
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