Two equations are given below:

a - 3b = 4

a = b - 2

What is the solution to the set of equations in the form (a, b) ?

(-2, - 2)

(-3, - 1)

(-9, - 7)

(-5, - 3)

Since the second equation gives a value for a, we can substitute it into the other equation to find a value for B.

Let's substitute b-2 into the first equation wherever there is an a.

a - 3b = 4

(b-2) - 3b = 4

b - 2 - 3b = 4

-2 - 2b = 4

-2b = 6

b = - 3

Now let's find a by substituting - 3 into either of the equations to find the value of a.

a = b - 2

a = - 3 - 2

a = - 5

So your solution set is (-5, - 3)