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5 March, 09:55

Second derivative test for:

y = e^x (x^2 - 7x + 13)

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Answers (1)
  1. 5 March, 11:42
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    Hello

    y = e^x (x^2 - 7x + 13)

    y' = (e^x) ' (x^2 - 7x + 13) + e^x (x^2 - 7x + 13) '

    y' = e^x (x^2 - 7x + 13) + e^x (2x-7)

    y" = e^x (x^2 - 7x + 13) + e^x (2)

    y"=e^x (x^2 - 7x + 15)
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