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11 February, 04:29

Find the axis of symmetry for this parabola y=-4x^2-8x-6 in an equation

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  1. 11 February, 05:20
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    Y = ax² + bx + c is the equation of a parabola:

    y = 4x² - 8x - 6 is our equation.

    The axis of symmetry in a parabola is x = - b/2a

    x = - (-8) / (2.4) = - 8/8 and x = - 1 (axis of symmetry
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