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9 August, 22:48

Jack is filling his new six person hot tub with a water hose. After 58 minutes, his hot tub has 318 gallons water. His hot tub holds 1,360 gallons of water. He adds another water hose that flows 50% faster. Find the constant of proportionality for the flow rate of the two water hoses combined? (round to nearest tenth)

A) 6.9

B) 8.2

C) 13.7

D) 16.4

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  1. 9 August, 23:16
    0
    Constant of proportionality?

    I can find the rate of change

    ok, so find first hose rate of change

    gallons/minue=318/58=159gal/29min

    y=159/29x for first hose

    2nd hose

    50% faster

    times 3/2

    477/58=2nd hose

    constant of poroprotinality

    y=kx

    assuming y=amount and x is the time

    add the rates

    159/29+477/58=795/58=13.7

    so the new one would be

    y=13.7x

    constant is 13.7

    C
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