For triangle ABC side a=19, side b=10, and angle A=141 find side c to the nearest whole number

Given the value of two sides and an angle to determine the value of the third side. Use Cosine Law:

a^2 = c^2 + b^2 - 2bc*cosA

a = 19

b = 10

A = 141 degrees

19^2 = c^2 + 10^2 - (2*10*c*cos (141))

solve for c