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25 July, 00:22

While visiting Yosemite National Forrest, Joe approximated the angle of elevation to the top of a hill to be 40 degrees. After walking 450 ft closer, he guessed that the angle of elevation had increased by 18 degrees. Approximately how tall is the hill?

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  1. 25 July, 00:54
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    Draw a diagram to illustrate the problem as shown in the figure below.

    Let h = the height of the hill.

    At position A, the angle of elevation is 40°, and the horizontal distance to the foot of the hill is x.

    By definition,

    tan (40°) = h/x

    h = x tan40 = 0.8391x (1)

    At position B, Joe is (x - 450) ft from the foot of the hill. His angle of elevation is 40 + 18 = 58°.

    By definition,

    tan (58°) = h / (x - 450)

    h = (x - 450) tan (58°) = 1.6003 (x-450)

    h = 1.6003x - 720.135 (2)

    Equate (1) and (2).

    1.6003x - 720.135 = 0.8391x

    0.7612x = 720.135

    x = 946.0523

    From (1), obtain

    h = 0.8391*946.0523 = 793.8 ft

    Answer: The height of the hill is approximately 794 ft (nearest integer)
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