What is the sum of the arithmetic sequence 6, 14, 22,

if there are 26 terms

Sum of nth term of arithmetic sequence is given by Sn = n/2[2a + (n - 1) d]

Here, a = 6, n = 26 and d = 14 - 6 = 8

S26 = 26/2[2 (6) + (26 - 1) 8] = 13[12 + 25 (8) ] = 2,756