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5 March, 15:48

Solve the system by substitution 0.3a + 0.1b = 1.3 4/3a + 1/3b = 6

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  1. 5 March, 18:19
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    0.3a+0.1b=1.3

    4/3a+1/3b=6

    First make the second problem into decmoals.

    4.3a+.3b=6

    Now move the 0.3a to the other side of the equal sign by subtracting

    0.1b=1.3-0.3a

    Now divide the 0.1 on both sides

    b=13-3a

    Now substitute the b in the second problem for 13-3a

    4.3a+.3 (13-3a) = 6

    Multiply the. 3 with 13 and - 3

    4.3a+3.9-.9a=6

    Subtract the 3.9 on both sides

    4.3a-.9a=2.1

    Subtract the 4.3a with the. 9a

    3.4a=2.1

    Now divide 3.4 on both sides

    a=.61

    Now substitute the a in the first problem for. 61

    b=13-3 (.61)

    Multiply the - 3 with. 61

    b=13-1.83

    Now subtract 13 and 1.83

    b=11.17

    Now your answer is

    a=.61

    b=11.17
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