Ask Question
6 July, 13:40

A population of 500 animals that decreases at an annual rate of 17%

+1
Answers (2)
  1. 6 July, 14:39
    0
    This is exponential decay of the form:

    f=ir^t, f=final amount, i=initial amount, r=rate, t=time in this case:

    p (t) = 500 ((100-17) / 100) ^t

    p (t) = 500 (0.83) ^t
  2. 6 July, 16:38
    0
    Answer : 0.17

    Have a wonderful day!
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A population of 500 animals that decreases at an annual rate of 17% ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers