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20 June, 18:22

In how many ways can 7 distinct red balls and 5 distinct blue balls be placed in a row such that all red balls are adjacent,

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  1. 20 June, 21:36
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    The blue can be placed before the red or the red before the blue.

    7 distinct balls have a permutation of 5040 while 5 distinct balls have a permutation of 120.

    Each permutation of the reds can be combined with each permutation of the blues giving 5040*120=604800.

    Double this to 1209600 to allow for the two positioning for red and blue.
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