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26 April, 18:26

Find the limit as x approaches pi/2 of (sinx/x)

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  1. 26 April, 19:46
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    That function is continuous everywhere except at x=0. That means this limit is calculated by plugging pi/2 into the function to get the answer directly.

    1 / (pi/2) = 2/pi

    So the limit of (sin x / x) as x approaches pi / 2 is 2 / pi
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