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Mathematics
Plato
26 April, 18:26
Find the limit as x approaches pi/2 of (sinx/x)
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Harper Dalton
26 April, 19:46
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That function is continuous everywhere except at x=0. That means this limit is calculated by plugging pi/2 into the function to get the answer directly.
1 / (pi/2) = 2/pi
So the limit of (sin x / x) as x approaches pi / 2 is 2 / pi
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