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14 April, 09:35

Joanne bought 3 baseball cards for $160. If the first card was as expensive as the combined price of the second and the third cards, and the second card cost $20 more than the third card, what is the price of the first card?

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  1. 14 April, 11:26
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    Let b represent the third card

    let (b+20) represent the second card

    let (2b+20) represent the first card

    (2b+20) + (b+20) + b=160

    4b+40=160

    4b=160-40

    4b=120

    4b/4=120/4

    b=30

    2b+20

    = 2 (30) + 20

    = 60+20

    = 80

    b+20

    = 30=20

    = 60

    Therefore, the first card was $80, the second card was $50 and the third card was $30.
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