2x - 5y = 3

x - 3y = 1

(4, 1)

(5, 2)

(7, 2)

(9, 3)

Assuming this a system of equations and you need the solution set, you can solve it by elimination or substitution--whichever you find easier. i'll use elimination:

2x - 5y = 3

x - 3y = 1

here, it'll be pretty easy to get your x values to match so you can cancel them out. just multiply your bottom equation by 2, then subtract:

2x - 5y = 3

- (2x - 6y = 2)

your 2x's cancel out and - 5y + 6y is simply y, so you're left with:

y = 1

that already gives you your answer, because you can see that the first ordered pair is the only pair with a y-value that's 1, but still, to check your x-value, you just plug your y-value into one of the equations:

x - 3 (1) = 1

x - 3 = 1

x = 4

so your solution is (4, 1).