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31 March, 04:04

Find three consecutive integers such that the sum of twice the smallest and 3 times the largest is 126.

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  1. 31 March, 06:34
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    X-smallest

    y middle

    z largest

    x+1=y

    y+1=z

    2x+3z=126

    2x + 3 (y+1) = 126

    2x+3y+3=126

    2x+3 (x+1) = 123

    5x=120

    x=24

    y=25

    z=26
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