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7 March, 12:27

How many real zeros does y = (x-8) ^3 + 12 have?

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  1. 7 March, 16:03
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    To get the zeroes, we will equate the given equation with zero and solve for x as follows:

    (x-8) ^3 + 12 = 0

    (x-8) ^3 = - 12

    x-8 = ∛-12

    x - 8 ≈ - 2.2894

    x ≈ - 2.2894 + 8

    x ≈ 5.71

    Based on the above, this equation has only one real zero
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