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Mathematics
Janessa
7 March, 12:27
How many real zeros does y = (x-8) ^3 + 12 have?
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Natalia Juarez
7 March, 16:03
0
To get the zeroes, we will equate the given equation with zero and solve for x as follows:
(x-8) ^3 + 12 = 0
(x-8) ^3 = - 12
x-8 = ∛-12
x - 8 ≈ - 2.2894
x ≈ - 2.2894 + 8
x ≈ 5.71
Based on the above, this equation has only one real zero
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