Solve for x in the equation x^2-8x+41=0

Question

Mathematics

Christopher Kennedy

23 February, 12:10

Solve for x in the equation x^2-8x+41=0

+2

Answers (2)

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Aggie · Answer 1

X = [ - (-8) + / - sqrt ((-8) ^2 - 4*41) ] / 2

x = (8 + sqrt (-100) / 2 and (8 - sqrt (-100) / 2

4 + or - 5i

Olsen · Answer 2

First, you do x^2-8 which = - 8. Then, you drop the rest. After that, you combine like terms. Which that gives you 49. So your equation looks like this ... 33-8x=0. You then subtract 33 to both sides and your equation looks like this, - 8x = - 33. Now all you do is divide by - 8 and your answer is x=4.125.

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