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8 June, 06:19

12x^a y^b / (-6x^a y) ?

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  1. 8 June, 09:26
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    12 / ( - 6) = - 2;

    x^a / x^a = 1;

    y^b / y = y^ (b - 1);

    12x^a y^b / (-6x^a y) = ( - 2) x 1 x y^ (b - 1) = - 2y^ (b - 1);
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