Select the exclusion that fits best with this problem. 3x^2y^2-6xz/6x^2yz

Choices

x = 0

x, y, z = 0

1 + y + y^2, y = 0, 1 - y = 0

a, b = 0, a^2 + ab + b^2 = 0

2x - 1 = 0, 4x^2 + 2x + 1 = 0

For this case we have the following expression:

3x ^ 2y ^ 2-6xz / 6x ^ 2yz

From here, we must exclude all values that make the denominator equal to zero.

We have then:

6x ^ 2yz = 0

Therefore, the results are:

x = 0

y = 0

z = 0

Answer:

The exclusion that fits best with this problem is:

x, y, z = 0