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17 February, 01:12

The speed of a moving sidewalk at an airport is 6 ft/sec. a person can walk 51 ft forward on the moving sidewalk in the same time it takes to walk 7 ft on a nonmoving sidewalk in the opposite direction. At what rate wools a person walk on a moving sidewalk?

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  1. 17 February, 05:00
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    Distance = rate*time

    Let v be speed of person walking.

    6t + vt = 51

    vt = 7

    Solve for t:

    6t + 7 = 51

    t = 44/6 = 22/3

    Sub in to find v:

    v (22/3) = 7

    v = 21/22

    The speed a person walks is 21/22 ft/sec
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