Using the definition of even and odd functions explain why y = sin x + 1 is neither even or odd?

Can you show how you worked it out cause I'm not sure on how to plug it in exactly

A function is even if, for each x in the domain of f, f ( - x) = f (x).

The even functions have reflective symmetry through the y-axis.

A function is odd if, for each x in the domain of f, f ( - x) = - f (x).

The odd functions have rotational symmetry of 180º with respect to the origin.

For y = without x + 1 we have:

Let's see if it's even:

f (-x) = sin (-x) + 1

f (-x) = - sin (x) + 1

It is NOT even because it does not meet f ( - x) = f (x)

Let's see if it's odd:

f (-x) = sin (-x) + 1

f (-x) = - sin (x) + 1

It is NOT odd because it does not comply with f ( - x) = - f (x)

Answer:

It is not even and it is not odd.