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7 April, 07:40

Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations. Hint: Use your knowledge of factoring polynomials and identities for imaginary numbers.

x^3-27i

+1
Answers (1)
  1. 7 April, 10:53
    0
    I^3=-i

    therefor - 27i = (3i) ^3

    so we can get a sum of 2 perfect cubes

    a^3+b^3 = (a+b) (a^2-ab+b^2)

    so

    remember that i²=-1

    x^3 + (3i) ^3 = (x+3i) (x²-3xi-1)
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