The area of a triangular block is 49 square inches. If the base of the triangle is twice the height, how long are the base and the height of the triangle?

1) Formula: area = height * base / 2

2) Call x the height:

height = x

base = 2x

3) State the equation:

(x) (2x) = 49 in^2

4) Solve the equation:

2x^2 = 49 in^s

x^2 = (49/2) in^2

x = √ (49/2) in

x = 7√2 / 2 in = 3.5 √2 in

5) Solution:

height = 3.5 √2 in and base = 7√2 in

6) Verification: area = (7√2 in) (3.5√2 in) = 49 in^2

Answer: height = 3.5√2 in and base = 7√2 in.