Chris needs to make a 500 L of a 35% acidic solution. He has only two of the acidic solutions available, a 25% solution and a 50% solution. How many litres of each acidic solution should he mix? Create a system to solve?

Yes, very fun, not

ok

one way is table or

solutions amount x and y

x+y=500

x=25%

y=50%

0.25x+0.5y=0.35 (500)

we have

x+y=500

0.25x+0.5y=0.35 (500)

0.25x+0.5y=175

solve

multiply second equation by 100

25x+50y=17500

divide everybody by 25

x+2y=700

now we have

x+y=500

x+2y=700

multiply first equation by - 1 and add to second equaiton

-x-y=-500

x+2y=700 +

0x+1y=200

y=200

sub

x+y=500

x+200=500

x=300

300L of the 25% and 200L of the 50%