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19 September, 22:19

Find the product of (3x + 7y) ^2

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Answers (2)
  1. 19 September, 23:05
    0
    So I do the box method

    3x*3x = 9x^2

    3x*7y = 21xy

    7y*3x=21xy

    7y*7y = 49y

    Add together 21xy plus 21xy

    So you are left with:

    9x^2+42xy+49y
  2. 20 September, 00:47
    0
    9x^2+42xy+49y in terms of (a+b) ^2
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