Ask Question
Today, 05:59

A spherical balloon is inflated so that its volume is increasing at the rate of 2 ft3/min. How rapidly is the diameter of the balloon increasing when the diameter is 1.7 feet?

+4
Answers (1)
  1. Today, 09:43
    0
    According to the question requirements

    v = 4/3*pi*r^3

    dv/dt = 4*pi*r^2*dr/dt

    when

    d = 1.7

    r = 0.85

    and

    dv/dt = 2

    2 = 4*pi * (0.85) ^2*dr/dtthus the the speed of increasing of the balloon's diameter is

    dr/dt = 1 / (2pi * (0.85) ^2)

    = 0.2203 ft/min
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A spherical balloon is inflated so that its volume is increasing at the rate of 2 ft3/min. How rapidly is the diameter of the balloon ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers