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29 June, 04:52

What are the dimensions of a rectangle that has a perimeter of 74 units and an area of 102 square units?

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  1. 29 June, 08:08
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    A) 2L + 2W = 74

    B) L * W = 102

    L = 102 / W then substituting this into equation A

    A) 204/W + 2W = 74

    A) 204 + 2W^2 = 74W

    A) 2W^2 - 74W + 204 = 0

    W = 34 and L = 3 OR

    W = 3 and L = 34
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