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23 February, 12:44

The length of the sides of a triangular garden are 10m 11m 13m. Find the measure of the angle opposite the longest side to the nearest tenth of a degree

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  1. 23 February, 14:42
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    C^2=a^2+b^2-2abcosC

    13^2=10^2+11^2-2*10*11*cos (°)

    169=100+121-220cos (°)

    220cos (°) = 100+121-169

    220cos (°) = 52

    cos (°) = 13/55

    °=cos-1 (13/55)

    °=76.328°
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