Based on a survey conducted by Greenfield Online, 25 - 34-year-olds spend the most each week on fast food. The average weekly amount of $44 was reported in a May 2009 USA Today Snapshot. Assuming that weekly fast food expenditures are normally distributed with a standard deviation of $14.50, what is a probability that a person in this age group will spend more than $60 on fast food in a week?

Question

Mathematics

Immanuel

7 June, 17:46

Based on a survey conducted by Greenfield Online, 25 - 34-year-olds spend the most each week on fast food. The average weekly amount of $44 was reported in a May 2009 USA Today Snapshot. Assuming that weekly fast food expenditures are normally distributed with a standard deviation of $14.50, what is a probability that a person in this age group will spend more than $60 on fast food in a week?

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Jorge Palmer · Answer 1

The correct answer is P = 0.1357.

In solving for the probability (P) that the 34-year olds will spend more than $60 on fastfood, the mean and the standard deviation is to be taken into account. The mean (μ) being the $44 average weekly expenditure; while the standard deviation (σ) is $14.50. The formula goes this way P (X > 60) = P (X-μ > 60-44) = P (X-μ/σ > 60-44/14.50).