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20 April, 00:44

2sin^ (-2490) + tan 1410

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  1. 20 April, 03:56
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    2sin² (-2490) + tan 1410=2sin² (-330-6*360) + tan (330+3*360) =

    =2sin² (-330) + tan (330) = 2 sin² (30-1*360) + tan (-30) =

    =2sin² (30) - tan (30) = 2 (1/2) ²-√3/3=1/2-√3/3) = (3-2√3) / 6

    Answer: 2 sin² (-2490) + tan (1410) = (3-2√3) / 6 (≈-0.07735 ...)
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