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27 June, 20:42

Find f. f ''' (x) = cos (x), f (0) = 4, f ' (0) = 2, f '' (0) = 6

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  1. 27 June, 22:33
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    Given that every integration has constant C, and is solved by the 0 conditions stated in the problem;

    f''' (x) = Cos (x)

    f'' (x) = sin (x) + 6 after f'' (0) = 6

    f' (x) = - cos (x) + 6x + 2 after f' (0) = 2

    f (x) = - sin (x) + 3x^2 + 2x + 4 after f (0) = 4
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