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Mathematics
Cain
8 November, 18:40
A1=1, an = 4a n-1 - 1
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Grady Hudson
8 November, 22:25
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for part (a) find the sum of the first n terms of the arithmetic series. for part (b) find n for the given sum Sn.
45. 3+8+13+18+23 + ...
a. n=20
b. Sn=366
46. 50+42+34+26+18 + ...
a. n=40
b. Sn=182
47. - 10 + (-5) + 0+5+10 + ...
a. n=19
b. Sn=375
48. 34+31+28+25+22 + ...
a. n=32
b. Sn=-12
49. 2+9+16+23+30 + ...
a. n=68
b. Sn=1661
50. 2+16+30+44+58 + ...
a. n=24
b. Sn=2178
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