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8 November, 18:40

A1=1, an = 4a n-1 - 1

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  1. 8 November, 22:25
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    for part (a) find the sum of the first n terms of the arithmetic series. for part (b) find n for the given sum Sn.

    45. 3+8+13+18+23 + ...

    a. n=20

    b. Sn=366

    46. 50+42+34+26+18 + ...

    a. n=40

    b. Sn=182

    47. - 10 + (-5) + 0+5+10 + ...

    a. n=19

    b. Sn=375

    48. 34+31+28+25+22 + ...

    a. n=32

    b. Sn=-12

    49. 2+9+16+23+30 + ...

    a. n=68

    b. Sn=1661

    50. 2+16+30+44+58 + ...

    a. n=24

    b. Sn=2178
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