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Mathematics
Tasha
24 July, 18:15
Examples of no solution equations
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Carleigh Hancock
24 July, 19:43
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If you have an equation of the form:
ax²+bx+c=0, and b²-4ac<0, no solutions exist.
Why?
ax²+bx=-c
x² + (b/a) * x=-c/a
(x+b / (2a)) ² - (b / (2a)) ²=-c/a
(x+b / (2a)) ²-b² / (4a²) = - c/a
(x+b / (2a)) ²=b² / (4a²) - c/a
(x+b / (2a)) ² = (b²-4ac) / (4a²)
x+b / (2a) = + or - (√ (b²-4ac)) / (2a)
b²-4ac is the discriminant of this quadratic equation, and as it sits underneath a square root sign, it cannot be equal to a value less than zero. If b²-4ac<0, no solutions exist.
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