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1 March, 09:26

A theater charges $50 per ticket for seats in section a, $40 per ticket for seats in section b, and $20 per ticket for seats in section

c. for one play, 9,500 tickets were sold for a total of $335,000 in revenue. if 500 more tickets in section b were sold than the other two sections combined, how many tickets in each section were sold?

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  1. 1 March, 10:48
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    The first thing we must do for this case is to define variables.

    We have then:

    x: ticket for seats in section a

    y: ticket for seats in section b

    z: ticket for seats in section c

    We write the system of equations:

    50x + 40y + 20z = 335000

    x + y + z = 9500

    y = x + z + 500

    Solving the system we have:

    x = 1500

    y = 5000

    z = 3000

    Answer:

    ticket for seats in section a = 1500

    ticket for seats in section b = 5000

    ticket for seats in section c = 3000
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