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Solve the equation x^2-4x-12=0 two ways. By factoring and by Quadratic formula

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  1. Today, 21:37
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    By factoring, find two values j and k which satisfy two conditions, jk=ac=-12 and j+k=b=-4, so j and k must be 2 and - 6 so the factors are:

    (x+2) (x-6) = 0

    So x=-2 and 6

    By the quadratic formula, x = (-b±√ (b^2-4ac)) / (2a), in this case:

    x = (4±√ (16+48)) / 2

    x = (4±√64) / 2

    x = (4±8) / 2

    x=2±4

    x=-2 and 6
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