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20 June, 14:09

An object moves along the x-axis, its position at each time t> 0 given by / "x (t) = 81/2*t^2-3/4*t^4/" Determine the time interval (s), if any, during which the object slows down.

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  1. 20 June, 16:24
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    You can say an object slow down when the acceleration is negative which can be observed on a negative slope during the graph of acceleration, from a position equation lets derive 2 times to attain the acceleration equation

    x (t) = 81/2*t^2-3/4*t^4

    V (t) = 81X - 3t^3

    A (t) = 81 - 9t^2

    81 - 9t^2 < 0

    t^2 > 9

    -3 > t > 3
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