What are the first three terms of a geometric sequence in which a5=25 and the common ratio is 5?

Te sequence of this GP: a₁, a₂, a₃, a₄, a₅

WE know that the last term in a GP = a₁ (r) ⁿ⁻¹

Last term = a₅ = 25 and r = 5, and n=5 (given), Then:

25 = a₁ (5) ⁵⁻¹ = a₁ (5) ⁴ = 625 a₁

25 = 625 a₁ hence a₁ = 25/625, a₁ = 1/25

a₁ = 1/25

a₂ = (1/25) x 5 = 1/5

a₃ = (1/5) x 5 = 1

a₄ = (1) x 5 = 5

a₅ = 5 x 5 = 25