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Mathematics
Jacquelyn Chavez
21 January, 15:13
Given cosθ=1/3, find sin (90-θ)
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Steve Oneal
21 January, 15:33
0
Cos θ=1/3
cos θ=sen (90-θ)
therfore:
sen (90-θ) = 1/3
To chek
θ=arc cos 1/3=70.53º
sin (90-θ) = sin (90º-70.53º) = sin 19.47≈0.3333≈1/3
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