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21 January, 15:13

Given cosθ=1/3, find sin (90-θ)

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  1. 21 January, 15:33
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    Cos θ=1/3

    cos θ=sen (90-θ)

    therfore:

    sen (90-θ) = 1/3

    To chek

    θ=arc cos 1/3=70.53º

    sin (90-θ) = sin (90º-70.53º) = sin 19.47≈0.3333≈1/3
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