The length of a rectangle is 6 yd longer than its width. if the perimeter of the rectangle is 44 yd, find its area.

Let's call the length L and the width w.

perimeter = 2L + 2w

44 = 2L + 2w

the length is 6 yards longer than the width. so L = w + 6.

plug this into the equation. 44 = 2 (w+6) + 2w

44 = 2w + 12 + 2w

44 = 4w + 12

32 = 4w

w = 8

L = w + 6

L = 8 + 6

L = 14

area = Lw

area = 8 (14)

area = 112 yd²