The population of a pack of wolves is 88. the population is expected to grow at a rate of 2.5% each year. what function equation represents the population of the pack of wolves after t years?

a. f (t) = 88 (0.025) ^t

b. f (t) = 88 (1.25^) t

c. f (t) = 88 (2.5) ^t

d. f (t) = 88 (1.025) ^t

Question

Mathematics

Lauren Cooper

13 June, 18:53

The population of a pack of wolves is 88. the population is expected to grow at a rate of 2.5% each year. what function equation represents the population of the pack of wolves after t years?

a. f (t) = 88 (0.025) ^t

b. f (t) = 88 (1.25^) t

c. f (t) = 88 (2.5) ^t

d. f (t) = 88 (1.025) ^t

+1

Answers (1)

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Essence Jimenez · Answer 1

D

First year: 88 + 88 * 2.5% = 88 + 88 * 0.025 = 88 * 1.025

Second year: 88 * 1.025 + 88 * 1.025 * 2.5% = 88 * 1.025 + 88 * 1.025 * 0.025 = 88 * 1.025 * 1.025 = 88 * 1.025^2

The population of a pack of wolves is 88. the population is expected to grow at a rate of 2.5% each year. what function equation represents the population of the pack of wolves after t years?a. f (t) = 88 (0.025) ^tb. f (t) = 88 (1.25^) tc. f (t) = 88 (2.5) ^td. f (t) = 88 (1.025) ^t

The population of a pack of wolves is 88. the population is expected to grow at a rate of 2.5% each year. what function equation represents the population of the pack of wolves after t years?

a. f (t) = 88 (0.025) ^t

b. f (t) = 88 (1.25^) t

c. f (t) = 88 (2.5) ^t

d. f (t) = 88 (1.025) ^t