The faces of a tetrahedron die are numbered 1 to 4. If each of the 4 sides is equally likely to land down, what is the probability that the 2 does not end up face down?

Question

Mathematics

Terrell Harrington

27 August, 21:15

The faces of a tetrahedron die are numbered 1 to 4. If each of the 4 sides is equally likely to land down, what is the probability that the 2 does not end up face down?

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Aaden · Answer 1

Hello!

If there is 4 faces and 1/4 chance of any side end up face down, we just have to decrease one chance, so, the chance of the face "2" does not end up face down is equal the sum of the chances of the others faces end up face down, so, we have: 3/4.

Hugs!