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13 June, 01:12

Paulo makes a sequence of numbers.

He chooses a starting number and then subtracts equal amounts each time.

The third number in his sequence is 45.

The tenth number is - 32.

What is the first number in his sequence.

Show your method.

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Answers (2)
  1. 13 June, 01:41
    0
    45 - - 32 = 45 + 32 = 77.

    10 - 3 = 7.

    77 / 7 = 11.

    Paulo takes 11 away from each number.

    11 + 11 = 22.

    45 + 22 = 67.

    The first number was 67.
  2. 13 June, 04:29
    0
    The sequence is an Arithmetic Progression.

    T = a + (n-1) d.

    Where a = first term.

    d = common difference.

    n = Number of term

    let the first number = a.

    Sequence = a, a - d, a-2d, a-3d, ...

    3rd = a - 2d = 45 ... (i)

    10th = a - 9d = - 32 ... (ii)

    (i) minus (ii).

    (a - 2d) - (a - 9d) = 45 - (-32)

    a - 2d - a + 9d = 77

    -2d + 9d = 77

    7d = 77. Divide by 7.

    d = 77/7 = 11.

    Substitute d = 11, in (i)

    a-2d = 45.

    a - 2 (11) = 45

    a - 22 = 45.

    a = 45 + 22 = 67,

    Therefore first term = 67.
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