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6 June, 10:13

If - 5e^x^2 y=x and y (-5) = 0, find y′ (-5) by implicit differentiation

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  1. 6 June, 12:04
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    Differentiate:

    -5*2 (xe^x^2) y-5e^x^2dy/dx=1

    -5e^x^2 (2xy+y') = 1

    When x=-5, y=0:

    -5e²⁵y'=1, so y' (-5) = - eˉ²⁵/5
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