The perimeter of a rectangle is 62 meters. if the width were doubled and the length were increased by 21 meters, the perimeter would be 120 meters. what are the length and width of the original rectangle?

Question

Mathematics

Lauren Lester

9 February, 18:19

The perimeter of a rectangle is 62 meters. if the width were doubled and the length were increased by 21 meters, the perimeter would be 120 meters. what are the length and width of the original rectangle?

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Answers (1)

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Sheldon Barker · Answer 1

62=2w+2l

120 = 2 (2w) + 2 (l+21)

120=4w+2l+42

78 = 4w+2l

39=2w+l

39-2w=l

Use substitution

62=2w+2 (39-2w)

62 = 2w+78-4w

62 = - 2w+78

-16=-2w

8=w

Plug w in

62=2 (8) + 2l

62=16+2l

46=2l

23=l

Final answer: Width=8, Length=23