Ask Question
20 July, 21:27

Harlon wrote the equation A=18 (x^2+1) to find the area of a rectangle that has a length of x^2+1 and a width of 18. He solved for x and got x = ±√ (A/18 - 1). Which of the following is an equivalent equation for x?

A. x = ±√ (A-18/18)

B. x = ±√ (A+18/18)

C. x = ±√ (A-36)

D. x = ±√ (A+36)

+1
Answers (1)
  1. 20 July, 23:54
    0
    To solve for x in the equation for the area which was given to be, A = 18 (x^2 + 1), we divide both sides of the equation by 18 first.

    A/18 = x^2 + 1

    Then, we subtract 1 from both sides of the equation,

    A/18 - 1 = x^2

    Then, we simplify the expression in the left side of the equation,

    (A - 18) / 18 = x^2

    And finally, obtain the square root from both sides of equation,

    Sqrt ((A-18) / 18) = x

    The expression equivalent to this is letter A.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Harlon wrote the equation A=18 (x^2+1) to find the area of a rectangle that has a length of x^2+1 and a width of 18. He solved for x and ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers