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6 February, 00:27

Express r=2cos (theta) + 2sin (theta) as a cartesian function.

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  1. 6 February, 04:14
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    The function is in polar coordinates.

    When this is the case, to pass to rectagular (cartesian) coordinates you use:

    x = r cos (theta)

    y = r sin (theta)

    Then,

    x = [2cos (theta) + 2sin (theta) ]cos (theta) =

    = 2 [cos (theta) ]^2 + 2sin (theta) cos (theta) = 2 [cos (theta) ]^2 + sin (2theta)

    y = [2cos (theta) + 2sin (theta) ]sin (theta) =

    = 2 cos (theta) sin (theta) + 2[sin (theta) ]^2 = sin (2theta) + 2[sin (theta) ]^2
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