A shopkeeper bought some eggs at ¢15 each. Six of them were broken while the rest were sold at ¢20 each. If he made a profit of $4.80, find how many eggs he bought.

In the given problem it is already stated that the cost of each eggs is 15 cent. Out the total eggs bought 6 were broken. The rest of the eggs were sold for 20 cents each and the profit made was $4.80.

Cost of the 6 broken eggs = (6 * 0.15)

= 0.9 cents

Let us assume that the number of eggs bought = x

Then we can write the equation as

0.2x - (0.15x - 0.9) = 4.80

0.2x - 0.15x + 0.9 = 4.80

0.05x = 4.80 - 0.9

0.05x = 3.9

x = 3.9/0.05

= 78

So the number of eggs bought by him is 78