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9 August, 08:14

Verify

(2cos2x) / (sin2x) = cotx - tanx

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Answers (1)
  1. 9 August, 10:06
    0
    Cos2x = (cosx) ^2 - (sinx) ^2;

    sin2x = 2sinxcosx;

    Then, (2cos2x) / (sin2x) = 2[ (cosx) ^2 - (sinx) ^2 ] / (2sinxcosx) = [ (cosx) ^2 - (sinx) ^2 ] / (sinxcosx) = (cosx) ^2 / (sinxcosx) - (sinx) ^2 / (sinxcosx) = cosx/sinx - sinx/cosx = cotx - tanx;
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