The perimeter of a triangle is 39 inches. The second side is 9 times as long as the first side. The third side is 1 inch longer than the second side. Find

the length of each side.

Perimiter=x+y+z

x is 9 times as long as y

z is 1 longer than x

translate

x=9 times y or x=9y

z=1+x

subsitute 9y for x in the z=1+x equation

z=1+9y

subsitute z=1+9y and x=9y in the equation

9y+y+1+9y=39

add like terms

19y+1=39

subtract 1 from both sides

19y=38

divide by 19

y=2

subsitute

x=9y

x=9 (2)

x=18

z=1+9y

z=1+9 (2)

z=1+18

z=19

the side legnths are

first side: 2 in

second side: 18 in

third side: 19 in